por lucianofloripa » Sex Nov 20, 2009 12:38
por Cleyson007 » Sex Nov 20, 2009 13:04
![d(a,b)=\sqrt[2]{{({x}_{2}-{x}_{1})}^{2}+({y}_{2}-{y}_{1})^2}](/latexrender/pictures/9b48877ce3b6fd72cfbb4ced2edf289e.png "d(a,b)=\sqrt[2]{{({x}_{2}-{x}_{1})}^{2}+({y}_{2}-{y}_{1})^2}")
![5=\sqrt[2]{{(0-r)}^{2}+{(-2-2)}^{2}}](/latexrender/pictures/855ee6b0da9f16c3fccc111c91f9a329.png "5=\sqrt[2]{{(0-r)}^{2}+{(-2-2)}^{2}}")
![5=\sqrt[2]{{r}^{2}+16}](/latexrender/pictures/3188cff322e280311d98337bb6f8ece0.png "5=\sqrt[2]{{r}^{2}+16}")
![{5}^{2}=(\sqrt[2]{{r}^{2}+16})^2](/latexrender/pictures/afb627d6646a3da344994451bcea3295.png "{5}^{2}=(\sqrt[2]{{r}^{2}+16})^2")
por lucianofloripa » Sex Nov 20, 2009 14:51
por Cleyson007 » Sex Nov 20, 2009 18:36
. 
por lucianofloripa » Qua Nov 25, 2009 11:30
por lucianofloripa » Qua Nov 25, 2009 14:33
por lucianofloripa » Qui Nov 26, 2009 11:25
Voltar para Geometria Analítica
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![\frac{\sqrt[]{\sqrt[4]{8}+\sqrt[]{\sqrt[]{2}-1}}-\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}-1}}}{\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}+1}}}](/latexrender/pictures/981987c7bcdf9f8f498ca4605785636a.png "\frac{\sqrt[]{\sqrt[4]{8}+\sqrt[]{\sqrt[]{2}-1}}-\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}-1}}}{\sqrt[]{\sqrt[4]{8}-\sqrt[]{\sqrt[]{2}+1}}}")
![\sqrt[]{2}](/latexrender/pictures/f21662d1cabab6e8b273a4b6f1cd663a.png "\sqrt[]{2}")
(dica : igualar a expressão a 
e elevar ao quadrado os dois lados)