Derivada

por **Fernandobertolaccini** » Dom Jul 06, 2014 22:55

Derivada

por Fernandobertolaccini » Dom Jul 06, 2014 22:55

$Sendo F(x) = cos(arcsenx) , Calcule : F'(\frac{\sqrt[]{3}}{2})$ $Resp:(-\sqrt[]{3})$

por **young_jedi** » Seg Jul 07, 2014 20:20

Re: Derivada

por young_jedi » Seg Jul 07, 2014 20:20

$f'(x)=-sen(arcsen(x)).\frac{1}{cos(arcsen(x))}$

$f'(x)=\frac{-x}{cos(arcsen(x))}$

$f'\left(\frac{\sqrt3}{2}\right)=\frac{-\left(\frac{\sqrt3}{2}\right)}{cos(arcsen\left(\frac{\sqrt3}{2}\right))}$

$f'\left(\frac{\sqrt3}{2}\right)=\frac{-\left(\frac{\sqrt3}{2}\right)}{cos\left(\frac{\pi}{3}\right)}$

$f'\left(\frac{\sqrt3}{2}\right)=\frac{-\left(\frac{\sqrt3}{2}\right)}{\frac{1}{2}}$

$f'\left(\frac{\sqrt3}{2}\right)=-\sqrt3$

Derivada

Derivada

Derivada

Re: Derivada

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